The general
mechanism for finding percentage yield is as follows:
1. Balance
the chemical equation
2. Find the limiting reagent
3. Find the theoretical yield
4. Find the actual yield
5. Find the
percentage yield
1. Balancing
The Chemical Equation:
The first step in finding
theoretical and percentage yield is to balance the relevant chemical
equation.
The first step in balancing any
equation, is to write out the correct chemical formula:
For
Example: CH4 + O2 -->
CO2 + H2O
Is
the reaction for the combustion of methane (CH4) in excess oxygen (O2)
To balance the equation, you need to find the smallest whole
number coefficients so that each element is balanced in the reaction. To
solve for these coefficients, use a system of equations:
For the current example:
aCH4 + bO2 -->
cCO2 + dH2O
Multiplying each
element by the coefficient gives you the following equations:
Equation 1: a = c
When the equation is
balanced, there will be (1 x a) Carbon atoms from methane on the reactants
side and (1 x c) Carbon atoms from carbon dioxide on the products side
Equation 2: 4a = 2d
When the equation is
balanced, there will be (4 x a) Hydrogen atoms from methane on the
reactants side and (2 x d) hydrogen atoms from water on the products side
Equation 2(i): 2a = d
Note
that Equation 2 can be simplified to this format
Equation 3: 2b = 2c + d
When the equation is
balanced, there will be (2 x b) oxygen atoms from oxygen gas on the
reactant side, (2 x c) oxygen atoms from carbon dioxide on the products
side and (1 x d) oxygen atoms from water on the product side.
Equation 3(i): b = 2a
Note that this
formula results by substituting Equation 1 and Equation 2(i) into Equation 3 and simplifying
To solve for a, b, c
and d:
First take the smallest whole number that satisfies Equation 1, which is simply
a = c =1
Then, substitute that value into Equation 2(i):
2a = d
2(1) = d
d = 2
and Equation 3(i):
b = 2a
b = 2(1)
b = 2
Your coefficients are a = 1, b = 2, c = 1 and d = 2
When writing your balanced equation, the coefficient 1 is assumed and can
be omitted, yielding the formula:
CH4 + 2O2 -->
CO2 + 2H2O
2. Finding The Limiting Reagent:
This is the reactant which the product yield depends on, as it is not in
excess. To determine which reactant is the limiting reagent:-
1(a). Divide the
mass (in grams) of the reactant by its molecular weight (g/mol)
OR
(b).
Multiply the amount used (in ml) by its density, then divide by its molar
mass
2.
Multiply the mass (your answer from steps 1(a) or 1(b)) by the
number of moles of the reactant used in the reaction.
Example:
salicylic acid +
acetic anhydride « acetylsalicylic acid (ASA) + acetic acid
Salicylic
acid: (0.211 g) / (138.1 g/mol) x 1 = 0.00153 mol
Acetic
anhydride: (0.480 mL) x (1.08 g/mL) /
(102.1 g/mol) x 1 = 0.00508 mol
Therefore,
salicylic acid is the limiting reagent, since there are less moles of that
than there are of acetic anhydride.
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